Chemistry Content Reviewer (Contract)

We’re looking for passionate Chemistry content reviewers to work online and ensure accuracy and clarity in assets that help students test their chemistry skills (short explanations of specific chemistry skills, and practice problem sets)

As a contract Chemistry Content Reviewer, you'll receive the following:

Reliable Payments: Timely, reliable payments twice a month
Independence: No waiting, no assignments, and a massive library of questions for you to choose from
Flexibility: Work from anywhere, at any time, completely online
Supportive Staff: Access to a supportive in-house team to answer your questions

What we’re looking for:

Expertise in chemistry
Strong English-language Reading and Writing skills
Proofreading and editing skills

Do you think you can be a Chemistry Content Reviewer for Study.com? Please apply now!

About Study.com

At Study.com, our quest is to make education fun and accessible. We’re working to help students with high quality answers to hard questions that they may have on their academic journey. We recently ranked 10th on Virtual Vocations' top 25 list of best partners for remote work in 2021, and we're growing our team of contractors even further!

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Please describe your qualifications to review and edit difficult homework questions in your chosen subject(s). Write exactly 3 sentences.*

Read the answer below. Check for grammar, accuracy, plagiarism, etc., then provide the writer of this answer with specific feedback that will help them understand what they need to fix.
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Question:
Suppose you have 600.0 grams of room temperature water (20.0 degrees Celsius) in a thermos. You drop 90.0 grams of ice at 0.00 degrees Celsius into the thermos and shut the lid.
(a) What is the equilibrium temperature of the system?
(b) How much ice is left (in grams)?

Answer:

a. the equilibrium temperature of the system is 7.74 celsius
b. There will be 0 grams of ice left

The problem can be solved by breaking it into smaller pieces. The amount of energy needed to melt the ice is Wi×Hf, where Wi is the weight of the ice. In addition, the 90 grams of water obtained from the ice must be heated from 0°C, which is the temperature of the ice, to the final temperature Tf.

Where does the energy for melting the ice come from? Since the cup is insulated, the heat has to come from the 600 grams of water at 20°C. The amount of heat required to melt the ice and to increase the temperature of the resulting water to the final temperature is equal to the heat lost by the 100 grams of water. This can be expressed by an equation:

Wi×Hf + Wi×Sh×(Tf - 0°C) = Ww×Sh×(Twi - Tf)
Where
Wi = weight of ice = 90g
Hf = Heat of fusion = 80 calories/gram
Ww = weight of water = 600g
Tf = final temperature,
Twi = initial water temperature = 20°C
Sh = Specific Heat for water = 1.0 calories per gram per °C
(90×80) + (20×1)×(Tf - 0°C) = (600×1)×(20°C - Tf)
7200 + 20Tf = 12000 - 600Tf
620Tf = 4800
Tf = 4800/620 = 7.74°C
Using the equation above, where the final temperature is 0°C
and the weight of the ice is unknown, we have:
Wi×80 = 600×1×20
The maximum amount of ice that could be melted is:
Wi = 12000/80 = 150 grams
Then, use the initial mass of ice – amount melted
= 150 g – 150g = 0 grams of ice*

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Chemistry Content Reviewer (Contract)

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